I mean why should one ten millionth of the distance from Earth’s equator to its pole have anything to do with the force per area from a column of water under one Earth gravity?
OK… OK… shit happens… I can accept that.
But then answer me this:
Why is it that ten decibars (ie: one bar) is ab/used as an approximation of the pressure of a column of our atmosphere under one Earth gravity?
Am I missing some common definition underlying this?
I don’t understand the Calchemy definition, but in the GNU units program the definitions are as follows (allowing the program to work them out from first principles):
bar = 100000 pascal
pascal = 1 newton/m^2
atmosphere = 1.01325 bar
barye = 1e-06 bar # CGS unit
The unit is named after Blaise Pascal, noted for his contributions to hydrodynamics and hydrostatics, and experiments with a barometer. The name pascal was adopted for the SI unit newton per square metre (N/m2) by the 14th General Conference on Weights and Measures in 1971.
So we have two geocentric coincidences relating to the same physical dimension (pressure). I’m not serious enough about this to immediately take off and write a Mathematica combinatorial script to measure the probability of this. But it is rather a delightful coincidence.
The ‘;’ operator is the lazy man’s way of telling Calchemy to do the combinatorial search for all multiplicative expressions that result in a physical dimension consistent with the unit given after the ‘?’, and then calculate that multiplicative expression’s value with appropriate unit scaling. In the present case, I could have just typed ‘*’ wherever I had typed ‘;’:
It also includes a ‘1’ before each of the units if a constant is not given, so a perhaps more understandable “solution by dimensional analysis” would be:
1 d_sea_water * 1 gravity * 1 meter ? 1 deci~bar
which is, of course, equivalent to, but more intuitive than: