What Happens after You Fall into a Black Hole?

Yes “spaghettification” is a word. Actually, at the present time there is a great deal of controversy about what happens when you fall past the event horizon of a super-massive black hole (assuming it does not have an accretion disc which would be radiating enormous amounts of energy).

The original classical general relativity description of spacetime in the vicinity of a black hole suggested that nothing special happened when you fell past the event horizon of a black hole other than your now being unavoidably on a trajectory toward the central singularity. But quantum calculations in strongly curved spacetime suggest that there may be intense radiation at the event horizon due to infalling particles and energy, which would be blue-shifted to the speed of light. This hypothetical phenomenon is called the “black hole firewall”. At the moment there is no experimental evidence to determine whether it actually exists, but it is possible analysis of black hole mergers from their gravitational wave signatures may offer clues to the puzzle.


Hang on a moment! If we accept the Big Bang hypothesis (and who does not?), then everything in the Universe started off within an unimaginably small volume containing unimaginably large energy/mass at some extreme temperature with (presumably) an infinitely large gravitational force. Or, to put it differently, the Universe started off inside a Black Hole.

What does the inside of a Black Hole look like? Circumspice.

By the way, the really strange factor is that the entropy in that unbelievably hot, dense, energetic singularity was also extremely low. We have to postulate that the material of the Big Bang was incredibly well ordered.


The proper radial acceleration of a static non-inertial detector observer at fixed r outside the black hole is g = (GM/r^2)[1 - 2GM/c2r]^-1/2

The Hawking black body radiation temperature is

T =hg/ckB

Therefore the temperature is infinite at the surface event horizon of the black hole where

1 - 2GM/c^2r = 0

However, a freely falling observer has T = 0 because his g = 0, but if the nearby static observer firing his rockets feels the heat will that heat conduct and burn the passing free falling observer?

Note in the Tic Tac able to control the tilt of its own light cone with small amounts of energy, the black hole will not be dangerous and we can explore its interior without fear by neutralizing the black hole’s curvature inside the Tic Tac.

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